SOLUTION: Each of three fraternities must each send two members to a meeting with the university administration. One fraternity has 20 members, another has 31 members and the third has 45

Algebra ->  Permutations -> SOLUTION: Each of three fraternities must each send two members to a meeting with the university administration. One fraternity has 20 members, another has 31 members and the third has 45       Log On


   



Question 999130: Each of three fraternities must each send two members to a meeting with the university administration. One fraternity has 20 members, another has 31 members and the third has 45 members. Determine the total number of ways in which these six people could be selected.
Answer by ikleyn(52776) About Me  (Show Source):
You can put this solution on YOUR website!
.
Each of three fraternities must each send two members to a meeting with the university administration. One fraternity has 20 members, another has 31 members and the third has 45 members. Determine the total number of ways in which these six people could be selected.
----------------------------------------------------------------

C%5B20%5D%5E2 . C%5B31%5D%5E2 . C%5B45%5D%5E2 = %2820%2A19%29%2F2 . %2831%2A30%29%2F2 . %2845%2A44%29%2F2 = 10*19*31*15*45*22 = 87466500 ways.