SOLUTION: how many different product of 3 digits can be formed from the digits 2,5 and 7 without repetition ?

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Question 990789: how many different product of 3 digits can be formed from the digits 2,5 and 7 without repetition ?
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
How many different products of 3 digits??

Only one product of the three digits 2,5, and 7 is possible, that is:

2x5x7 = 2x7x5 = 5x2x7 = 5x7x2 - 7x2x5 = 7x5x2 = 70.

Maybe you didn't know that "product" means "what you get when you multiply".

Maybe you didn't want any product at all.

Maybe you just wanted to know how many ways 2, 5, and 7 can be rearranged.

That would be 6 ways: 257, 275, 527, 572, 725, 752.

Or, maybe you wanted this kind of a product:

3 ways to choose the first digit
times
2 ways remaining to chose for the second digit, and
times
1 way remaining to choose the third digit.

Which is 

3x2x1 or 3! or 3P3 or "number of permutations of 3 things taken 3 at a time"
or 6.

Edwin