A committee has 25 members;15 whom are women and 10 men.
-How many ways can a subcommittee of 8 be chosen to work on a project if
*anyone of the committee be chosen?
(25 members, Choose 8) = 25C8 = 1081575
*at most 2 women can be chosen?
Three cases:
Case 1. Choose no women at all. (That's all men)
(10 men members, Choose 8) = 10C8 = 45
Case 2. Choose 1 woman and 7 men.
(15 women, Choose 1)*(10 men, Choose 7) = 15C1*10C7 = 15*120 = 1800
Case 3. Choose 2 woman and 6 men.
(15 women, Choose 2)*(10 men, Choose 6) = 15C2*10C6 = 105*210 = 22050
Grand total: 45 + 1800 + 22050 = 23895
Edwin