SOLUTION: A teacher has 18 boys and 11 girls in her class. In how many ways can she select 8 of the children to be in a play if she must select 4 boys and 4 girls.

Algebra ->  Permutations -> SOLUTION: A teacher has 18 boys and 11 girls in her class. In how many ways can she select 8 of the children to be in a play if she must select 4 boys and 4 girls.      Log On


   

Question 983994: A teacher has 18 boys and 11 girls in her class. In how many ways can she select 8 of the children to be in a play if she must select 4 boys and 4 girls.
Answer by Timnewman(323) About Me  (Show Source):
You can put this solution on YOUR website!
Hi dear,
Since 4 out of 18 are boys,4 out 11 are girls are to be selected,
Multiply there individual combination as follows;


= %2818%21%2F%2814%21%2A4%21%29%29%2A%2811%21%2F%287%21%2A4%21%29%29
= 3060*330
= 1009800ways
HOPE THIS HELPS;
Timnewman;