SOLUTION: find the limit as t approaches 3 of {{{(t^3-27)/(t-3)}}}

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Question 980460: find the limit as t approaches 3 of %28t%5E3-27%29%2F%28t-3%29
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
t^3 - 27 factors to (t-3)(t^2 + 3t + 9) when you use the difference of cubes factoring rule

So

Now plug in t = 3 t%5E2+%2B+3t+%2B+9=3%5E2%2B3%283%29%2B9+=+27

So the limiting value is 27