SOLUTION: there are 10 teams competing in the national math competition if only the first four teams are awarded medals how many possible arrangments of first second third and fourth are pos
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Question 960975: there are 10 teams competing in the national math competition if only the first four teams are awarded medals how many possible arrangments of first second third and fourth are possible Answer by Edwin McCravy(20054) (Show Source):
Choose the recipient for 1st medal any of 10 ways
Choose the recipient for 2nd medal any of the 9 remaining ways
Choose the recipient for 3rd medal any of the 8 remaining ways
Choose the recipient for 4th medal any of the 7 remaining ways
Answer: 10*9*8*7 = "10 Position 4" = 10P4 = = 5040 ways.
Edwin
