Question 949682: A book club offers a choice of 3 books from a list of 30. How many different selections of 3 different books each can be made from this list?
I TRIED 30*29*28= 24360 THEN DIVIDED THAT BY 3 AND GOT 8120
BUT IT WAS STILL WRONG.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! A book club offers a choice of 3 books from a list of 30. How many different selections of 3 different books each can be made from this list?
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The 1st choice is 1 of 30, then 29, then 28
--> 30*29*28 = 24360
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Choosing A, B & C is the same as A, C & B or C, B & A, etc.
There are 6 possible arrangements for 3 books, 3*2*1 = 6
24360/6 = 4060 possibilities
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