SOLUTION: A theater has 48 seats arranged in 8 rows of 6 seats each. three friends buy tickets separately. what is probability they will end up in same row?

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Question 943371: A theater has 48 seats arranged in 8 rows of 6 seats each. three friends buy tickets separately. what is probability they will end up in same row?
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
A theater has 48 seats arranged in 8 rows of 6 seats each. three friends buy
tickets separately. what is probability they will end up in same row?
Only the number of rows matters. [The 48 and 6 are irrelevant.]

Suppose the friends are A, B and C.

 %22%22=%22%22
   [Since "AND" tells us to multiply probabilities] 
 %22%22=%22%22

%281%29%2A%281%2F8%29%2A%281%2F8%29 %22%22=%22%22 1%2F64

[Notice that the first probability is 1 because it is certain
that A will be assigned to some row.]

Edwin