SOLUTION: The question is: Four students are running in an election for class representative on the student council. In how many different ways can the four names be listed on the ballot?

Algebra ->  Permutations -> SOLUTION: The question is: Four students are running in an election for class representative on the student council. In how many different ways can the four names be listed on the ballot?       Log On


   

Question 935980: The question is: Four students are running in an election for class representative on the student council. In how many different ways can the four names be listed on the ballot?
Since there are four students to pick from and there's one position, the notation for this should be 4P1= 4!/(4-1)!= 4. However the answer states that there are 24 ways, how do you yield that answer and why?
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The 1st is 1 of 4.
Then 1 of 3, then 2, etc
--> 4*3*2*1 = 24

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
The question is: Four students are running in an election for class representative on the student council. In how many different ways can the four names be listed on the ballot?
Ans:: 4P4 = 4! = 24 ways
----------------------------------
Since there are four students to pick from and there's one position, the notation for this should be 4P1= 4!/(4-1)!= 4. However the answer states that there are 24 ways, how do you yield that answer and why?
---------
Explanation::
1st listed:: 4 ways to choose
2nd listed:: 3 ways to choose
3rd listed:: 2 ways to choose
last listed:: 1 way to choose
-----
Total ways = 4*3*2*1 = 24
---------------------------
Cheers,
Stan H.
--------------