SOLUTION: Good day! My question goes here, "How many 5-digit even numbers can be formed out of the digits 2, 4, 5, 8 and 9 without repetition?"

Algebra ->  Permutations -> SOLUTION: Good day! My question goes here, "How many 5-digit even numbers can be formed out of the digits 2, 4, 5, 8 and 9 without repetition?"       Log On


   



Question 935765: Good day! My question goes here, "How many 5-digit even numbers can be formed out of the digits 2, 4, 5, 8 and 9 without repetition?"
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

Consider the 5-digit number as blanks: _ _ _ _ _
The last digit must be even. Since we have three even numbers (2,4,8). The last digit can be filled in 3 ways. Since repetition is not allowed, we can fill out the rest blanks in ways,3 ways,2 ways, and 1 way.
1%2A+2+%2A+3%2A+4+%2A3+=+72 ways ; so, 72 5-digit even numbers can be formed