SOLUTION: how many 3 digits number can be formed from the digit 2,3,5,6,7,and 9 which are divisible by 5 and non of the digits is repeated ?

Algebra ->  Permutations -> SOLUTION: how many 3 digits number can be formed from the digit 2,3,5,6,7,and 9 which are divisible by 5 and non of the digits is repeated ?      Log On


   

Question 928825: how many 3 digits number can be formed from the digit 2,3,5,6,7,and 9 which are divisible by 5 and non of the digits is repeated ?
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
We choose the last digit 1 way, (as 5).
We choose the first digit any of 5 ways {2,3,6,7,9}
We choose the middle digit any of 4 ways.

Answer: 1*5*4 = 20 ways:

235, 265, 275, 295,
325, 365, 375, 395,
625, 635, 675, 695,
725, 735, 765, 795,
925, 935, 065, 975.

Edwin