Let A be the 1st pile of 3 plates.
Let B be the 2nd pile of 3 plates.
Let C be the pile with 2 plates.
Each time you pick up all 8 plates can be represented by
a seqeunce of 8 which contains 3 A's, 3 B's and 2 C's,
For instance, the sequence of 8:
B,C,A,C,B,A,B,A represents the case where we pick up a plate from
pile B, then a plate from pile C, then one from A, C, and so
on until the 8th plate is picked from pile A.
In each such sequence there are C(8,3) positions for the 3 A's
to go.
That leaves 5 remaining positions for the B's to go. So there
are then C(5,3) to choose positions for the B's to go. Then the
remaining 2 are where the C's go.
Answer: C(8,3)C(5,3)C(2,2) = 56*10*1 = 560 ways to pick up
all the plates.
Edwin