SOLUTION: a group of 34 people contains 24 woman and 10 men. a committee of 6 is to be randomly chosen. what is the probability that a) 4 woman and 2 men are chosen? b)the committee will h

Algebra ->  Permutations -> SOLUTION: a group of 34 people contains 24 woman and 10 men. a committee of 6 is to be randomly chosen. what is the probability that a) 4 woman and 2 men are chosen? b)the committee will h      Log On


   

Question 923515: a group of 34 people contains 24 woman and 10 men. a committee of 6 is to be randomly chosen. what is the probability that
a) 4 woman and 2 men are chosen?
b)the committee will have all members of the same sex?
c)atleast one woman is chosen?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
34 people: 24W, 10M
6 randomly chosen.
P( 4W and 2M) = +%2824C4%29%2810C2%29%2F%2834C6%29+
P(all same sex) = %28%2824C6%29+%2B+%2810C6%29%29%2F%2834C6%29
P(at least one woman) = 1 - P(no woman) = 1 - %2810C6%29%2F%2834C6%29