SOLUTION: n!/(n-1)!=5
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Question 897931
:
n!/(n-1)!=5
Found 2 solutions by
jim_thompson5910, stanbon
:
Answer by
jim_thompson5910(35256)
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By definition
n! = n*(n-1)*(n-2)*(n-3)...(3)*(2)*(1)
We can rewrite "(n-1)*(n-2)*(n-3)...(3)*(2)*(1)" as simply "(n-1)!"
So, n! = n*(n-1)!
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n!/(n-1)!=5
[n*(n-1)!]/(n-1)!=5
n = 5
Answer by
stanbon(75887)
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put this solution on YOUR website!
n!/(n-1)!=5
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[n(n-1)!/(n-1)!] = 5
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n = 5
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Cheers,
Stan H.
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