SOLUTION: how many 3 digit numbers can be formed using 0,1,2, and 3 if no 2 digits are the same? the solution used was H T U = 3 x 3 x 2 = 18 i didn't get how hundreds, tens, and unit

Algebra ->  Permutations -> SOLUTION: how many 3 digit numbers can be formed using 0,1,2, and 3 if no 2 digits are the same? the solution used was H T U = 3 x 3 x 2 = 18 i didn't get how hundreds, tens, and unit       Log On


   



Question 890639: how many 3 digit numbers can be formed using 0,1,2, and 3 if no 2 digits are the same?
the solution used was H T U = 3 x 3 x 2 = 18
i didn't get how hundreds, tens, and unit became 3 x 3 x 2. is there a way for me to easily understand?
thanks in advance.

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
For each of the H possible choices for the hundreds digit,
you have T choices for the tens digit,
making H%2AT choices for the first two digits.
Then for each of those H%2AT choices,
you have U choices for the last digit,
for a total of
%28H%2AT%29%2AU=H%2AT%2AU choices.

You cannot use 0 as the first (hundreds) digit, because it would really make a two-digit number.
You have only 3 choices (1, 2, or 3) for the hundreds digit.
The number of possible choices for the hundreds is H=3 .

For each of those choices, you have have eliminated one of the digits listed above,
but for the other digits you can also use 0.
As you have 3 digits not yet used that you can use for the tens and units digits,
the number of possible choices for the tens digit is T=3 .

Each possible choice of hundreds and tens digits leaves you two digits not yet used,
so the number of possible choices for the units digit is U=2 .

H%2AT%2AU=3%2A3%2A2=18