SOLUTION: Hi I really need help with these questions please. Im not good at questions pertaining cards. 1) From a standard deck of 52 cards (no jokers) a) In how many ways could you ch

Algebra ->  Permutations -> SOLUTION: Hi I really need help with these questions please. Im not good at questions pertaining cards. 1) From a standard deck of 52 cards (no jokers) a) In how many ways could you ch      Log On


   



Question 887263: Hi I really need help with these questions please. Im not good at questions pertaining cards.
1) From a standard deck of 52 cards (no jokers)
a) In how many ways could you choose a red five or a club?
b) In how many ways could you choose a jack or a red card?

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Hi I really need help with these questions please. I'm not good at questions pertaining cards.
You just need to know that there are 4 suits, 2 red, hearts and diamonds,
 and , and 2 black, spades and clubs, ♠ and ♣ and 13 of each rank.
Ace,2,3,4,5,6,7,8,9,10,Jack,Queen, and King.

1) From a standard deck of 52 cards (no jokers)

That's these 52 cards:


A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 
A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦
A♠   2♠   3♠   4♠   5♠   6♠   7♠   8♠  9♠  10♠  J♠  Q♠  K♠  
A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣ 

a) In how many ways could you choose a red five or a club?

That's any of these 15 cards:

                    5♥ 
                    5♦

A♣   2♣   3♣   4♣   5♣   6♣   7♣   8♣  9♣  10♣  J♣  Q♣  K♣ 

out of the whole pack of 52, so that's 15 out of 52 or 15%2F52
b) In how many ways could you choose a jack or a red card?
That's any of these 28 cards

A♥   2♥   3♥   4♥   5♥   6♥   7♥   8♥  9♥  10♥  J♥  Q♥  K♥ 
A♦   2♦   3♦   4♦   5♦   6♦   7♦   8♦  9♦  10♦  J♦  Q♦  K♦
                                                J♠  
                                                J♣
out of the whole pack of 52, so that's 28 out of 52 or 28%2F52 which
reduces to 7%2F13.

Edwin