SOLUTION: I will form a 6 letter code word using only the first 12 letters of the alphabet and allow repeated letters. If I select a code word at random find the probability that the code wo

Algebra ->  Permutations -> SOLUTION: I will form a 6 letter code word using only the first 12 letters of the alphabet and allow repeated letters. If I select a code word at random find the probability that the code wo      Log On


   



Question 875360: I will form a 6 letter code word using only the first 12 letters of the alphabet and allow repeated letters. If I select a code word at random find the probability that the code word has no vowels

Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
The first 12 letters of the alphabet are

ABCDEFGHIJKL

Of those, 3 are vowels and 9 are consonants.

So the probability that each one is a consonant is 9%2F12 or 3%2F4

So the probability that the 1st and the 2nd and the 3rd are

consonants is expr%283%2F4%29%2Aexpr%283%2F4%29%2Aexpr%283%2F4%29 = %283%2F4%29%5E3 = 27%2F64

Edwin