Question 871528: I would be so grateful if you could assist. I have a very simple question, I believe, which is as follows.
A Hebrew word consists of 3 consonants, and the Hebrew alphabet of 22 consonants.
How many permutations of 3 can be extracted from 22?
Also how many permutations of 2 consonants and how many of 4?
The answer should provide a theoretical maximum for the number of Hebrew words in existence, now and/or in the past. The numbers will form part of some research on the Hebrew origins of English.
I hope you can help. I have done a calculation myself, but don't trust my own judgement, I regret. Such was algebra when I was at school.
Danny Israel.
Found 2 solutions by Edwin McCravy, richwmiller:
Answer by Edwin McCravy(20054)   (Show Source):
You can put this solution on YOUR website! A Hebrew word consists of 3 consonants, and the Hebrew alphabet of 22 consonants.
How many permutations of 3 can be extracted from 22?
I will assume the consonants do not have to be different.
That is, they could be like XXZ, XZZ or even XXX.
Then there would be 26×26×26 = 17,576
Also how many permutations of 2 consonants
22×22 = 484
and how many of 4?
22×22×22×22 = 234,256
The numbers would be fewer if there are rules about using the
same letter. FI, if, say, as in English, there cannot be more
than 2 of the same letter in a row. Also in English, words do
not end in j, v, or q, and few end in vowels other than e. Few
words begin with a double letter. q must be followed by u.
Many spelling rules will reduce the numbers. Also, are there
no vowels in Hebrew?
Edwin
Answer by richwmiller(17219)  (Show Source):
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