SOLUTION: How many different positive five-digit integers can be formed if the second digit must be 3, the fourth digit cannot be either 1 or 2, and digits may be repeated?
Algebra ->
Permutations
-> SOLUTION: How many different positive five-digit integers can be formed if the second digit must be 3, the fourth digit cannot be either 1 or 2, and digits may be repeated?
Log On
Question 866964: How many different positive five-digit integers can be formed if the second digit must be 3, the fourth digit cannot be either 1 or 2, and digits may be repeated? Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! Assuming the first digit can't be 0
9*1*10*8*10=7200
if the first can be zero
10*1*10*8*10=8000
