SOLUTION: How can 5000! (a large factorial) be found numerically? Someone, call him Igor for this problem :) Anyway - wants to know how many groups of 50 are there in 5000. I started wo

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Question 858584: How can 5000! (a large factorial) be found numerically?
Someone, call him Igor for this problem :) Anyway - wants to know how
many groups of 50 are there in 5000.
I started working this using nCr = n! / r!(n-r)!
nCr = 5000C50, and chose to settle for a ball-park (estimated figure) quote,
yet have no idea although the number C must lie between astronomical and ∞.
50! is solvable, but was wondering if 5000! can be partitioned or reduced
so a hand calculator could work it. Any shortcuts here would be appreciated!

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
You do not need to calculate a number as astronomical as 5000!,
because ,
and that is slightly less astronomical.
According to the combinations function in the Excel spreadsheet program in my computer, 5000C50 is 2.2839%2A10%5E120 .
That must also an estimate, because there is no way it could calculate all 120 decimal places.
I also calculated 5000C50 as

Excel also calculated 5000%2A4999%2A4998%2A%22...%22%2A4953%2A4952%2A4951=6.9432%2A10%5E184 for me.
I do not know if you can do that with a calculator.
A crude approximation of 5000%21%2F4950%21=5000%2A4999%2A4998%2A%22...%22%2A4953%2A4952%2A4951
would be .
A better approximation for

would be 5000%2A4975%5E49=6.9475%2A10%5E184 .