SOLUTION: i have decide to host a party .in which 2 are from my family including me and 5 are my other friend .in total there are 7 persons in party of which 3 are males and 4 are females.
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Question 850837: i have decide to host a party .in which 2 are from my family including me and 5 are my other friend .in total there are 7 persons in party of which 3 are males and 4 are females.
A)3 persons are selected with replacement.What is the probability that my friends are short listed at least twice?
b) 4 persons are selected randomly without replacement.What is the probability that two males and females are selected? Answer by ewatrrr(24785) (Show Source):
Hi,
Note: shortlisted 2/3 of the time
'short listed' ... more family than friends in the group of 3
A. 2C2*5C1 are the 5 ways there are more family than friends:
P(shortlisted) = 2C2*5C1/7C3 = 5/35 = 1/7
P(shortlisted 2/3 of the time ) = (2/3)(1/7) = 2/21 = .0952
b. P =
