SOLUTION: assume that we want to seat Alex, Bonnie, Carl, Daria, Edith, and Frank in a row of six chairs. In how many ways can the seating be done if Alex and Bonnie must sit together.

Algebra ->  Permutations -> SOLUTION: assume that we want to seat Alex, Bonnie, Carl, Daria, Edith, and Frank in a row of six chairs. In how many ways can the seating be done if Alex and Bonnie must sit together.      Log On


   

Question 848988: assume that we want to seat Alex, Bonnie, Carl, Daria, Edith, and Frank in a row of six chairs. In how many ways can the seating be done if Alex and Bonnie must sit together.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
It's the number of permutation of the 5 things {AB,C,D,E,F}
plus the number of permutations of the 5 things {BA,C,D,E,F}

Answer 5!+5! = 2×5! = 2×120 = 240 ways.

Edwin