SOLUTION: I have 116 pieces of jewelry - 36 pair of earrings; 43 rings; 11 bracelets; 26 necklaces.
I have two holes in each ear; two rings at a time and two bracelets at a time.
My suga
Algebra ->
Permutations
-> SOLUTION: I have 116 pieces of jewelry - 36 pair of earrings; 43 rings; 11 bracelets; 26 necklaces.
I have two holes in each ear; two rings at a time and two bracelets at a time.
My suga
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Question 848148: I have 116 pieces of jewelry - 36 pair of earrings; 43 rings; 11 bracelets; 26 necklaces.
I have two holes in each ear; two rings at a time and two bracelets at a time.
My sugar daddy wants to know how many possible combinations of jewels I have available for my fashion choices.
Thanx!
Nancy Answer by ewatrrr(24785) (Show Source):
