SOLUTION: In a probability model, which of the following numbers could be the probability of an outcome: 0, 1.0002, -3.01,12/11 ,-1/2 ,5/4 , 1, 1.5

Algebra ->  Permutations -> SOLUTION: In a probability model, which of the following numbers could be the probability of an outcome: 0, 1.0002, -3.01,12/11 ,-1/2 ,5/4 , 1, 1.5      Log On


   



Question 745276: In a probability model, which of the following numbers could be the probability of an outcome:
0, 1.0002, -3.01,12/11 ,-1/2 ,5/4 , 1, 1.5

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The probability of any event MUST be between 0 and 1 (including both 0 and 1)

So you cannot have a probability of 1.0002, 12/11, 5/4 or 1.5 since these values are greater than 1

So cross those values off the list to get


0, 1.0002, -3.01,12/11 ,-1/2 ,5/4 , 1, 1.5

0, 1.0002, -3.01,12/11 ,-1/2 ,5/4 , 1, 1.5

0, -3.01, -1/2 , 1


You cannot have a probability of -3.01 or -1/2 since both are less than 0

Cross those numbers off the list to get

0, -3.01, -1/2 , 1

0,-3.01, -1/2, 1

0,1

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Answer:

Only the numbers 0 and 1 from the list would be possible probabilities.