SOLUTION: Ralph has seven different colors of leftover paint. Since there is not enough of any one color to paint all four walls of his room, he has decided to paint each wall a different co
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Question 737297: Ralph has seven different colors of leftover paint. Since there is not enough of any one color to paint all four walls of his room, he has decided to paint each wall a different color. How many different ways can he carry out his plan?
What I have so far -
The first wall can be any one of 7 colors.
The second wall can be any of the 6 remaining colors
The third can be any of 5 colors
There are 4 colors remaining to paint the last wall.
So there are 7 × 6 × 5 × 4 = 840 ways. But in permutation? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Ralph has seven different colors of leftover paint. Since there is not enough of any one color to paint all four walls of his room, he has decided to paint each wall a different color. How many different ways can he carry out his plan?
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Select sets of 4 cans from the 7 available:
Ans: 7C4 = 7C3 = (7*6*5)/(1*2*3) = 35
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Cheers,
Stan H.
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