SOLUTION: Ten students are to sit on a bench. If two particular student must not sit next to each other, how many sitting arrangement are possible?
Algebra ->
Permutations
-> SOLUTION: Ten students are to sit on a bench. If two particular student must not sit next to each other, how many sitting arrangement are possible?
Log On
Question 730191: Ten students are to sit on a bench. If two particular student must not sit next to each other, how many sitting arrangement are possible? Found 2 solutions by lynnlo, ikleyn:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! .
Ten students are to sit on a bench. If two particular student must not sit next to each other,
how many sitting arrangement are possible?
~~~~~~~~~~~~~~~~~~~~~~~~~~~
With no restrictions, 10! = 10*9*8*7*6*5*4*3*2*1 = 3628800 permutations/arrangements are possible.
With the restriction, we consider the pair of particular students as one block/item.
So, there are 2*9! different unwanted arrangements.
The factor 2 appeared since, two particular students can be ordered in 2 different ways.
So, the number of allowed arrangements is 10! - 2*9! = 3628800 - 2*(9*8*7*6*5*4*3*2*1) = 2903040.
ANSWER. The number of allowed arrangements is 2903040.