SOLUTION: I need help with this problem, it is multiplying and dividing factorials. In case you cannot tell: /= Division *= Multiplication 6!/2!4! * 5!/4!1! Thank you!

Algebra ->  Permutations -> SOLUTION: I need help with this problem, it is multiplying and dividing factorials. In case you cannot tell: /= Division *= Multiplication 6!/2!4! * 5!/4!1! Thank you!      Log On


   

Question 72163This question is from textbook Algebra 2
: I need help with this problem, it is multiplying and dividing factorials.
In case you cannot tell:
/= Division
*= Multiplication
6!/2!4! * 5!/4!1!
Thank you! This question is from textbook Algebra 2

Found 2 solutions by checkley75, jim_thompson5910:
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!

(6*5[4*3*2*1])/(2*1[4*3*2*1])(5[4*3*2*1])/([4*3*2*1]*1)
MANY OF THESE MULTIPLIERS CAN BE CANCELLED OUT FROM THESE FRACTIONS. ITEMS BRACKETED[] CAN BE CANCELLED. THUS
(6*5/2*1)(5/1) THUS WE HAVE
30/2*5/1=150/2=75

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
6!/2!4! * 5!/4!1! is equivalent to

Notice how there are repeating terms of 4*3*2*1
These terms cancel out.
%28%286%2A5%29%2F%282%2A1%29%29%2A%285%2F1%29Now just multiply and divide as you normally would
%286%2A5%2A5%29%2F%282%2A1%2A1%29
150%2F2
75