SOLUTION: A committee of 8 is to be selected out of 6 males and 8 females. In how many ways can it beformed so that the male way not be out numbered?
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Question 698570: A committee of 8 is to be selected out of 6 males and 8 females. In how many ways can it beformed so that the male way not be out numbered? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A committee of 8 is to be selected out of 6 males and 8 females. In how many ways can it beformed so that the male way not be out numbered?
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6males/2females: 6C6*8C2 = 1*28 = 28 ways
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5males/3females: 6C5*8C3 = 6*56 = 336 ways
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4males/4females: 6C4*8C4 = 15*70 = 1050 ways
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Total # of ways: 28+336+1050 = 1414
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Cheers,
Stan H.
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