SOLUTION: if f(x)=ax^2+2a and f(3)-f(1)=60, what is the value of a?
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Question 682825
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if f(x)=ax^2+2a and f(3)-f(1)=60, what is the value of a?
Answer by
jim_thompson5910(35256)
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f(x)=ax^2+2a
f(3)=a(3)^2+2a
f(3)=a*9+2a
f(3)=9a+2a
f(3)=11a
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f(x)=ax^2+2a
f(1)=a(1)^2+2a
f(1)=a*1+2a
f(1)=1a+2a
f(1)=3a
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f(3)-f(1)=60
11a - 3a = 60
8a = 60
a = 60/8
a =
15/2