SOLUTION: A class has 8 boys and 4 girls. A committee of 3 has to be chosen. In how many ways can at least 1 girl be chosen to the committee?

Algebra ->  Permutations -> SOLUTION: A class has 8 boys and 4 girls. A committee of 3 has to be chosen. In how many ways can at least 1 girl be chosen to the committee?      Log On


   



Question 650082: A class has 8 boys and 4 girls. A committee of 3 has to be chosen. In how many ways can at least 1 girl be chosen to the committee?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
A class has 8 boys and 4 girls. A committee of 3 has to be chosen.
In how many ways can at least 1 girl be chosen to the committee?
Total choices - committees with NO girls = 12C3 - 8C3*4C0