SOLUTION: 5 School children, including L & M, will be seated in a row of 5 seats. In how many ways can this be done id L & M must NOT sit together? I tried 5! (# of ways 5 can sit together

Algebra ->  Permutations -> SOLUTION: 5 School children, including L & M, will be seated in a row of 5 seats. In how many ways can this be done id L & M must NOT sit together? I tried 5! (# of ways 5 can sit together      Log On


   

Question 61819: 5 School children, including L & M, will be seated in a row of 5 seats. In how many ways can this be done id L & M must NOT sit together?
I tried 5! (# of ways 5 can sit together) - 4! (if L & M did sit together). Please help.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
5 School children, including L & M, will be seated in a row of 5 seats. In how many ways can this be done id L & M must NOT sit together?
I tried 5! (# of ways 5 can sit together) - 4! (if L & M did sit together). Please help.
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5! is the number of possible arrangements.
There are 4 ways L and M could sit together.
For each of those placements there are 3! ways
the remaining children could be arranged.
Final Answer: 5!-(4*3!)=96
Cheers,
Stan H.