SOLUTION: Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there. I am reallyngood at math but this chapter just doe

Algebra ->  Permutations -> SOLUTION: Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there. I am reallyngood at math but this chapter just doe      Log On


   



Question 613909: Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there.
I am reallyngood at math but this chapter just doesnt make sense to me. I get A's on all the assignments but it takes forever for.me to get the right answer. Please help. This is what i attempted to do.
7*6*5*4/4*3*2*1 with an answer of 35

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there.
Ans: 7C4 = (7*6*5*4)/(1*2*3*4) = 35
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Cheers,
Stan H.
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