SOLUTION: Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there.
I am reallyngood at math but this chapter just doe
Algebra ->
Permutations
-> SOLUTION: Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there.
I am reallyngood at math but this chapter just doe
Log On
Question 613909: Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there.
I am reallyngood at math but this chapter just doesnt make sense to me. I get A's on all the assignments but it takes forever for.me to get the right answer. Please help. This is what i attempted to do.
7*6*5*4/4*3*2*1 with an answer of 35 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Any four people on a committee of seven people can make a decision for the committee. How may groups of four people are there.
Ans: 7C4 = (7*6*5*4)/(1*2*3*4) = 35
========================================
Cheers,
Stan H.
=============