SOLUTION: what is the probability of meeting either a boy or chess player where there are 12 boys in chess, 6 girls in chess, 8 boys not in chess, and 20 girls not in chess?
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Question 612566: what is the probability of meeting either a boy or chess player where there are 12 boys in chess, 6 girls in chess, 8 boys not in chess, and 20 girls not in chess? Answer by solver91311(24713) (Show Source):
There are 20 boys and 26 girls, so there are 46 students altogether. There are 20 boys and 18 chess players, but 12 of the chess players are boys so they have already been counted, hence there are 20 boys plus 8 girl chess players in the set of successful outcomes. Divide the possible successes by the total possible choices.
John
My calculator said it, I believe it, that settles it
