SOLUTION: nP6=6(nP4) so far I have: n!/(n-6)!=6[n!/(n-4)!]

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Question 606393: nP6=6(nP4)
so far I have: n!/(n-6)!=6[n!/(n-4)!]
Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
dividing by n! and multiplying by (n-4)! ___ (n-4)! / (n-6)! = 6

(n-4)(n-5) = 6 ___ n^2 - 9n + 14 = 0

factoring ___ (n-7)(n-2) = 0