SOLUTION: If no digit appears more than once, how many 5-digit numbers can be formed from the digits 2, 3, 4, 6, and 7?

Algebra ->  Permutations -> SOLUTION: If no digit appears more than once, how many 5-digit numbers can be formed from the digits 2, 3, 4, 6, and 7?      Log On


   

Question 605873: If no digit appears more than once, how many 5-digit numbers can be formed from the digits 2, 3, 4, 6, and 7?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
There are 5 numbers to choose from, so there are 5! = 5*4*3*2*1 = 120 different 5-digit numbers.