SOLUTION: There are three couples who are attending a movie. If the two members of each couple wish to sit together during the movie, how many ways can the couples be seated?

Algebra ->  Permutations -> SOLUTION: There are three couples who are attending a movie. If the two members of each couple wish to sit together during the movie, how many ways can the couples be seated?       Log On


   



Question 599401: There are three couples who are attending a movie. If the two members of each couple wish to sit together during the movie, how many ways can the couples be seated?

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
6!/(2!*2!*2!)
=(6*5*4*3*2)/(4*2)
=6*5*3
=90 ways
.
Ed