SOLUTION: The digits of the locker combination consist of 3 one digit numbers, 1-9. If the digits are not repeated, what is the probabiliity of the combination being 1, 2, 3?

Click here to see ALL problems on Permutations

Question 585884: The digits of the locker combination consist of 3 one digit numbers, 1-9. If the digits are not repeated, what is the probabiliity of the combination being 1, 2, 3?
Found 2 solutions by jim_thompson5910, sudhanshu_kmr:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
There's only one combo of "123" out of $\large _9C_3 = \frac{9!}{3!(9-3)!}= 84$ different combinations. So the probability is
--------------------------------------------------------------------------------------------------------------
If you need more help, email me at jim_thompson5910@hotmail.com

Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you

Jim
--------------------------------------------------------------------------------------------------------------

Answer by sudhanshu_kmr(1152) (Show Source):
You can put this solution on YOUR website!

number of total possible combination = 9*8*7
probability of combination being 1,2,3 is : 1/(9*8*7)