SOLUTION: if i have to pick two numbers from 1 to 10, provided the first number can't be greater than the second number. How many possible way I can represent the two number. Please suggest

Algebra ->  Permutations -> SOLUTION: if i have to pick two numbers from 1 to 10, provided the first number can't be greater than the second number. How many possible way I can represent the two number. Please suggest       Log On


   



Question 563661: if i have to pick two numbers from 1 to 10, provided the first number can't be greater than the second number. How many possible way I can represent the two number. Please suggest the formula to use?
E.g.
12 - valid
21 - not valid

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If the 1st number is 1, the 2nd can be 2-10
If the 1st number is 2, the 2nd can be 3-10
If the 1st number is 3, the 2nd can be 4-10
-----------
This progression is
+9+%2B+8+%2B+7+%2B+6+%2B+5+%2B+4+%2B+3+%2B+2+%2B+1+=+45+
-------------
A formula would be if you can choose numbers
from 1 to n, then the possible arrangements of 2 numbers
the 1st being smaller than the 2nd
is (n-1) + (n-2) + (n-3) + . . . + 1
This sum is +%281%2F2%29%2An%2A%28n-1%29+
check:
for 1 to 10, +%281%2F2%29%2A10%2A9+=+90%2F2+
+90%2F2+=+45+
OK