SOLUTION: there is a game I play There are 6 soccer games. each game has a win draw win result. So it can be either a win for team a draw or win for team b. Now with 6 games and 3 possibili

Algebra ->  Permutations -> SOLUTION: there is a game I play There are 6 soccer games. each game has a win draw win result. So it can be either a win for team a draw or win for team b. Now with 6 games and 3 possibili      Log On


   



Question 556801: there is a game I play There are 6 soccer games. each game has a win draw win result. So it can be either a win for team a draw or win for team b.
Now with 6 games and 3 possibilities in each game, how many combinations is possible for all 6 games

Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!
Use formula : [n+r-1]C[r-1]
n+r+1 = 8, r-1 = 2
Total number of possible combinations = 8C2 = 28

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