SOLUTION: There are twenty women and fifteen men at a party. In how many distinct ways can you form ten couples consisting of one man and one woman?
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I thought it would be 15C10 * 2
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-> SOLUTION: There are twenty women and fifteen men at a party. In how many distinct ways can you form ten couples consisting of one man and one woman?
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I thought it would be 15C10 * 2
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Question 544179: There are twenty women and fifteen men at a party. In how many distinct ways can you form ten couples consisting of one man and one woman?
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I thought it would be 15C10 * 20C10 * 10! - you choose the men and the women; then the first woman has ten choices, the second has nine, etc. However, I'm not sure what really distinguishes this from a basic Fundamental Counting Theorem problem once you have chosen the men and women; under that interpretation, the 10! is unnecessary.
Thank you! Answer by sudhanshu_kmr(1152) (Show Source):
