SOLUTION: I am having a really hard time trying to figure out this question please help,all I know so far is that I should use permutation, but I don't know how: Question: A class consis

Algebra ->  Permutations -> SOLUTION: I am having a really hard time trying to figure out this question please help,all I know so far is that I should use permutation, but I don't know how: Question: A class consis      Log On


   



Question 528682: I am having a really hard time trying to figure out this question please help,all I know so far is that I should use permutation, but I don't know how:
Question:
A class consists of 60 ladies and 40 men. In how many ways can a president, vice president, treasurer and secretary be chosen if the treasurer must be a lady, the secretary must be a man and the student may not hold more than one office?
Thank you

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
I'll take shot at it, but you might want to get
a 2nd opinion
Since the treasurer must be a lady, there are
60 different ways that office can be filled
Since the Secretary must be a man, there are
40 ways that office can be filled.
There are +60%2A40+=+2400+ different ways
that the 2 offices can be held
-------------------------
Once the Treasurer and Secretary offices have
been filled, there are +59+%2B+39+=+98+
people left to fill President and Vice-President
There are +98%2A97+ different ways to fill
these 2 offices ( M or F doesn't matter )
-------------------------
The 4 offices can then be filled in
+60%2A40%2A98%2A97+ different ways.
( I lost calculator, you can finish )