SOLUTION: In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one.

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Question 484245: In a shipment of 11 CD players, two are defective. Find the probability that a sample of 3 CD players will contain no more than one defective one.
Answer by Tatiana_Stebko(1539) About Me  (Show Source):
You can put this solution on YOUR website!
P(no more than 1 defective one)=P(0 defective)+P(1 defective)
11 CD players, 2 defective, 11-2=9 not defective
P(0 defective)=%289C3%29%2F%2811C3%29


P(0 defective)=%289C3%29%2F%2811C3%29=84%2F165=28%2F55
P(1 defective)=%289C2%2A2C1%29%2F%2811C3%29

2C1=2
P(1 defective)=%2836%2A2%29%2F165=24%2F55
P(no more than 1 defective one)=P(0 defective)+P(1 defective)=28%2F55%2B24%2F55=52%2F55=0.945