SOLUTION: there are 10 alphabets a, b, c, d, e, f, g, h, i, j. How many arrangements are there where in 'a' precedes 'b' and 'c' precedes 'd'.

Algebra ->  Permutations -> SOLUTION: there are 10 alphabets a, b, c, d, e, f, g, h, i, j. How many arrangements are there where in 'a' precedes 'b' and 'c' precedes 'd'.      Log On


   

Question 483548: there are 10 alphabets a, b, c, d, e, f, g, h, i, j. How many arrangements are there where in 'a' precedes 'b' and 'c' precedes 'd'.
Answer by sudhanshu_kmr(1152) About Me  (Show Source):
You can put this solution on YOUR website!

Assume 'ab' and 'cd' are single letters, total 2+6= 8 letters.

Number of ways = 8! = 40320