SOLUTION: A SKYDIVING CLUB HAS 30 MEMBERS.THE CLUB MEMBERS JUMP IN PAIRS.HOW MANY DIFFERENT PAIRS OF SKYDIVERS ARE POSSIBLE.
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Question 482920: A SKYDIVING CLUB HAS 30 MEMBERS.THE CLUB MEMBERS JUMP IN PAIRS.HOW MANY DIFFERENT PAIRS OF SKYDIVERS ARE POSSIBLE. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A SKYDIVING CLUB HAS 30 MEMBERS.THE CLUB MEMBERS JUMP IN PAIRS.HOW MANY DIFFERENT PAIRS OF SKYDIVERS ARE POSSIBLE.
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Ans: 30C2 = (30*29)/(1*2) = 15*29 = 425 pairs
Cheers,
Stan H.
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