SOLUTION: A bag contains 5 red marbles and 4 yellow marbles. If you can only draw 3 marbles from the bag without replacement, in how many ways can you draw 2 reds and 1 yellow?
I keep co
Algebra ->
Permutations
-> SOLUTION: A bag contains 5 red marbles and 4 yellow marbles. If you can only draw 3 marbles from the bag without replacement, in how many ways can you draw 2 reds and 1 yellow?
I keep co
Log On
Question 452444: A bag contains 5 red marbles and 4 yellow marbles. If you can only draw 3 marbles from the bag without replacement, in how many ways can you draw 2 reds and 1 yellow?
I keep coming up with 40, but that's not an option. Please help! Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A bag contains 5 red marbles and 4 yellow marbles. If you can only draw 3 marbles from the bag without replacement,
In how many ways can you draw 2 reds and 1 yellow?
------
# of ways to draw 2 red: 5C2 = 10
# of ways to draw 1 yellow: 4C1 = 4
----
Total # of ways: 10*4 = 40
================================
Cheers,
Stan H.