SOLUTION: In how many ways can 5 students be chosen from a group of 8 males and 8 females, if you know that you must have exactly 3 females?

Algebra ->  Permutations -> SOLUTION: In how many ways can 5 students be chosen from a group of 8 males and 8 females, if you know that you must have exactly 3 females?      Log On


   



Question 451369: In how many ways can 5 students be chosen from a group of 8 males and 8 females, if you know that you must have exactly 3 females?
Answer by jorel1380(3719) About Me  (Show Source):
You can put this solution on YOUR website!
16 combined 5 at a time equals 16C5=
16x15x14x13x12x11x10!/10!x5x4x3x2x1=
8x3x14x13x11=48048
3 females represents 3/16 of the total amount of groups so:
3/16x48048=9009 different groups.