4th term of (4x+y)6 The formula for the kth term of (A + B)N is C(N,k-1)AN-k+1Bk-1 So substitute A = 4x, B = y, k = 4, N = 6 C(6,4-1)(4x)6-4+1y4-1 C(6,3)(4x)³y³ 20(4x)³y³ 20*4³x³y³ 20*64x³y³ 1280x³y³ Edwin