No, that's true because for instance from the letters
A,B,C,D
The 6 combinations of 2 are
{A,B}, {A,C}, {A,D}, {B,C}, {B,D}, {C,D}
where the order does not matter.
And since every one of those can be made into 2 permutations,
where order matters,
{A,B} can be made into the two permutations AB and BA.
{A,C} can be made into the two permutations AC and CA.
{A,D} can be made into the two permutations AD and DA.
{B,C} can be made into the two permutations BC and CB.
{B,D} can be made into the two permutations BD and DB.
{C,D} can be made into the two permutations CD and DC.
There are 6 combinations (where order does not matter),
and 12 permutations (where order does matter), so the
proposition is true, not false.
Edwin
