SOLUTION: 1. a baseball team has 3 catchers, 9 pitchers, 6 infielders, and 7 outfielders. In how many ways can a team of 9 be chosen for a game? 2.how many poker hands consist of 3 aces a

Algebra ->  Permutations -> SOLUTION: 1. a baseball team has 3 catchers, 9 pitchers, 6 infielders, and 7 outfielders. In how many ways can a team of 9 be chosen for a game? 2.how many poker hands consist of 3 aces a      Log On


   



Question 439731: 1. a baseball team has 3 catchers, 9 pitchers, 6 infielders, and 7 outfielders. In how many ways can a team of 9 be chosen for a game?
2.how many poker hands consist of 3 aces and 2 kings?
3.from a group of 6 representatives of labor, 5 representatives of business, 8 representatives of the general public, how many commitees of 6 can be formed consisting of 2 people from each group?
4. In how many ways can be eleven chosen out of batch of 15 players? how many of these will: A) include one particular player? B) exclude one particular player?

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
nCr=Combination of n things taken r at a time=n!/((n-r)!*r!)
1. On a baseball team there is 1 pitcher, 1 catcher, 4 infielders and 3 outfielders.
3*9*6C4*7C3
=27*15*35
=14,175 ways
.
Ed