SOLUTION: If there is a committee of 15 people, how many ways is there to divide it into 3 subcommittees of 3 people, 5 people, and 7 people.
Since order does not matter, i have tried 15C
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-> SOLUTION: If there is a committee of 15 people, how many ways is there to divide it into 3 subcommittees of 3 people, 5 people, and 7 people.
Since order does not matter, i have tried 15C
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Question 432741: If there is a committee of 15 people, how many ways is there to divide it into 3 subcommittees of 3 people, 5 people, and 7 people.
Since order does not matter, i have tried 15C3*15C5*15C7 I am not getting the given answer of 360360 though... Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! 15C7*8C5*3C3=360,360 Once they are on the committee of 7 you only have 8 bodies remaining for the committee of 5 and then only 3 left for the committee of 3.
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Ed
